For the reaction 2KlO3 → 2KCl + 3O2, how many moles of KlO3 are required to produce 250 g of oxygen?

10.42g

Explanation:

First you divide your sample by its molar mass, 250g÷15.999g which gives you around 15.63 moles. You get this because you are dividing your sample by its molar mass so for ever 15.999g it's 1 mol. Next you'll multiply 15.63 by 2 then divide it by 3 because that's the mole ratio of KIO3 and O2.

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the answer is b. dilution