Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial. Trial 1: 0.251Mg/ 1 x 1 mole mg/ 24.305Mg x 2mol MgO/2 mol Mg x 40.304 MgO/ 1 mole MgO=
Trial 2: 0.314Mg/ 1 x 1 mole mg/ 24.305Mg x 2mol MgO/2 mol Mg x 40.304 MgO/ 1 mole MgO=

The answer is c. 320 g

Okay well gravitational energy is matter forced by gravity making energy though the kinetic energy then the electric energy produces electricity from the kinetic energy and the kinetic energy gets its energy from the gravitational energy. was that the answer you wanted or something else?  

Idon't hope someone you

We first assume that this gas is an ideal gas where it follows the ideal gas equation. the said equation is expressed as: pv = nrt. from this equation, we can predict the changes in the pressure, volume and temperature. if the volume and the temperature of this gas is doubled, then the pressure still stays the same.