150. g of aluminum chloride in 0.450 liters of solution, what is the concentration? (any examples are helpful, thank you)

2.49 M

Explanation:

Step 1: Given data

Step 2: Calculate the moles AlCl₃ (solute)

The molar mass of AlCl₃ is 133.34 g/mol.

150. g × 1 mol/133.34 g = 1.12 mol

Step 3: Calculate the molar concentration of AlCl₃

Molarity is equal to the moles of solute divided by the liters of solution.

M = 1.12 mol/0.450 L = 2.49 M

56 moles of   lieter in chemistry

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole