When sodium azide is activated in an auto- mobile airbag, nitrogen gas and sodium are
produced according to the equation
2 NaN_(s) —> Na(s) + 3N2(g).
If 0.42 mol of NaN3 reacts, what mass of
nitrogen would result?
Answer in units of g

17.64 grams of nitrogen gas will be produced when 0.42 moles of sodium azide decomposes in the automobile airbag.

Explanation:

From the equation of reaction given below:

2 NaN₃ (s) > 2 Na (s) + 3 N₂

Two moles of sodium acid will decompose to produce two moles of sodium atom and three moles of nitrogen gas.

Mole ratio of sodium azide to nitrogen gas is 2 : 3

0.42 moles of sodium azide will produce 3/2 × 0.42 moles of nitrogen gas when It decomposes

Moles of of nitrogen gas produced = 0.63 moles

Molar mass of nitrogen gas = 2 × 14 = 28 g

Mass of nitrogen gas produced = 0.63 × 28 g

Mass of nitrogen gas produced = 17.64 g

Therefore, 17.64 grams of nitrogen gas will be produced when 0.42 moles of sodium azide decomposes in the automobile airbag.

your answer is a. the enthalpy of formation for a pure element in its standard state is always positive.