1. A rigid steel cylinder with a volume of 30 L is filled with nitrogen gas to a final pressure of 123 atm at 30 C. How many moles of N 2 gas does the cylinder contain? PV = nRT
K= + 273 =
C + 273 =
R=0.0821 L x atm/K x mol
PV = nRT
n=P XV=
R XT

10.063g / 10.00 ml = 1.0063 g/ml which rounds off to 4 sig figs as: 1.006 g/ml

The answer is b on plato.

Answer) by studying proton collisions hope this : )

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na