What is the molality of a solution containing 18.2 g HCl and 250. g of water?
(EZ Points here)

1.99M

Explanation:

Molality can be calculated by dividing the moles of solute by the mass of the solvent i.e.

Molality (M) = n of solute (mol) ÷ mass of solvent (kg)

Based on the information, mass of HCl (solute) = 18.2g, mass of solvent (water) = 250.0g

mole of solute = mass/molar mass

Molar mass of HCl = 1 + 35.5 = 36.5g/lol

mole = 18.2/36.5

mole = 0.499mol

Mass of solvent = 250.0g

In Kg, mass of water = 250/1000

= 0.250Kg

Molality = 0.499/0.250

Molality = 1.996

Molality of the solution = 1.99M

how to make a simple air condition

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error