What is the pressure exerted by 2.5 mol of gas with a temperature of 25 Celsius and a volume of 12.2 L

5.01 atm

Explanation:

To answer this question, we're going to use the PV=nRT equation, where in this case:

P = ?V = 12.2 Ln = 2.5 molR = 0.082 atm·L·mol⁻¹·K⁻¹T = 25 °C ⇒ 25 + 273.16 = 298.16 K

We input the data:

P * 12.2 L = 2.5 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

And finally solve for P:

P = 5.01 atm

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na

Sorry i dont understand the question can you rephase it?