1) Give all the mole-to-mole relationships (ratios) that exist in fraction form for the following reaction. (12 total) 2 Li2O2 + 2 CO2 2 Li2CO3 + O2​

1 mol Li₂O₂/mol CO₂ or 1 mol CO₂/mol Li₂O₂

2 mol Li₂CO₃/mol O₂ or 1 mol O₂/2 mol Li₂CO₃

1 mol Li₂O₂/mol Li₂CO₃ or 1 mol Li₂CO₃/mol Li₂O₂

2 mol Li₂O₂/mol O₂ or 1 mol O₂/2 mol Li₂O₂

1 mol CO₂/mol Li₂CO₃ or 1 mol Li₂CO₃/mol CO₂

2 mol CO₂/mol O₂ or 1 mol O₂/2 mol CO₂

Explanation:

The balanced chemical equation is:

2 Li₂O₂ + 2 CO₂ → 2 Li₂CO₃ + O₂

The mole-to-mole relationships are provided by the chemical stoichiometric coefficients (2 for Li₂O₂, 2 for CO₂, 2 for Li₂CO₃ and 1 for O₂).

We have to relate the moles of 1 compound to the moles of another compound in the equation. So, we can start writing the relationships between reactants (Li₂O₂ and CO₂)

2 moles of Li₂O₂ react with 2 moles of CO₂ → 2 mol Li₂O₂/2 mol CO₂= 1 mol Li₂O₂/mol CO₂ or 1 mol CO₂/mol Li₂O₂

Now, the relationships between products (Li₂CO₃ and O₂):

2 moles of Li₂CO₃ are produced when 1 mol of O₂ produced → 2 mol Li₂CO₃/1 mol O₂= 2 mol Li₂CO₃/mol O₂ or 1 mol O₂/2 mol Li₂CO₃

Finally, between reactants and products:

2 moles of Li₂O₂ produce 2 moles of Li₂CO₃ → 2 mol Li₂O₂/2 mol Li₂CO₃= 1 mol Li₂O₂/mol Li₂CO₃ or 1 mol Li₂CO₃/mol Li₂O₂

2 moles of Li₂O₂ produce 1 mol of O₂ → 2 mol Li₂O₂/1 mol O₂= 2 mol Li₂O₂/mol O₂ or 1 mol O₂/2 mol Li₂O₂

2 moles of CO₂ produce 2 moles of Li₂CO₃ → 2 mol CO₂/2 mol Li₂CO₃= 1 mol CO₂/mol Li₂CO₃ or 1 mol Li₂CO₃/mol CO₂

2 moles of CO₂ produce 1 mol of O₂ → 2 mol CO₂/1 mol O₂= 2 mol CO₂/mol O₂ or 1 mol O₂/2 mol CO₂

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