What is the Kinetic Energy (in J) of 41.0 moles of gold atoms (atomic mass = 197.0 g/mol) moving with a speed of 800 m/s?​

2584640 J

Explanation:

From the question given above, the following data were obtained:

Number of mole of gold = 41 moles

Molar mass of gold = 197 g/mol

Velocity (v) = 800 m/s

Kinetic energy (KE) =..?

Next, we shall determine mass of gold in Kg. This can be obtained as follow:

Number of mole of gold = 41 moles

Molar mass of gold = 197 g/mol

Mass of gold =?

Mass = mole × molar mass

Mass of gold = 41 × 197

Mass of gold = 8077 g

Convert 8077 g to Kg:

1000 g = 1 Kg

Therefore,

8077 g = 8077 g × 1 Kg / 1000 g

8077 g = 8.077 Kg

Finally, we shall determine the kinetic energy of the gold atom. This can be obtained as follow:

Velocity (v) = 800 m/s

Mass of gold = 8.077 Kg

Kinetic energy (KE) =..?

KE = ½mv²

KE = ½ × 8.077 × 800²

KE = ½ × 8.077 × 640000

KE = 2584640 J

Thus, the kinetic energy of the gold atom is 2584640 J

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