Calculate the number of grams of aluminum chloride produced when 8.6 moles of aluminum react with chlorine gas. 2 Al + 3 Cl2 -> 2 AlCl3

1148 grams

Explanation:

The balanced chemical reaction of this question is as follows:

2Al + 3Cl2 → 2AlCl3

Based on the equation above;

2 moles of Aluminum react to produce 2 moles of Aluminum chloride (AlCl3)

Therefore, 8.6 moles of aluminum will react to produce: 8.6 × 2/2

= 8.6moles of AlCl3.

Using mole = mass ÷ molar mass, to determine the number of grams.

Molar Mass of AlCl3 = 27 + 35.5(3)

= 27 + 106.5

= 133.5g/mol

Using mole = mass/molar mass

Mass = molar mass × mole

Mass = 133.5 × 8.6

Mass = 1148.1

Mass of AlCl3 = 1148 grams