The detector used in this experiment is called a Flame Ionization Detector (FID). As the different sample components come out of the end of the column and enter the detector, they pass into a flame and generate free electrons. The electrons are generated as a result of carbon atoms being converted to positively charged carbon ions during the combustion process. The response measured (i. e.# of electrons generated per unit time; the electrical current) is directly proportional to the carbon content of the component entering the detector. Predict which of the following compounds will generate the largest detector response per unit concentration. Assume the concentration of each compound is the same in the sample mixture analyzed by GC-FID. a. 2-methyl-1-propanol.
b. 1-butanol.
c. 2-methyl-1-butanol.
d. ethyl acetate.

c. 2-methyl-1-butanol.

Explanation:

As depicted in the question; the number of electrons produced is straightforwardly relative and directly proportional to the content and substance of carbon in the atom. So 2-methyl-1-butanol has the most highest and noteworthy carbon content (5carbons) among the accompanying species. So it will generate and create the biggest detector reaction response.

passed in september 1935, these laws are known as nuremberg laws.   they forbid jews from marrying but not directly forced them to divorce aryans. what is most noticeable is the fact that the jews were defranchised, meaning by this that they were not expected to have any civil rights, including the right to vote. the right answer is deprived of the right to vote.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole