Find the solution of equation 4cos^2 (theta) - 3 = 0 (in the interval [0, 2pi]

The solution to the answer is as follows:

4(cosx)^2 - 3 = 0 

Add 3 to each side 

4(cosx)^2 = 3 

Divide both sides by 4 

(cosx)^2 = 3/4 

Take the square root of each side 

cosx = sqrt(3/4) or -sqrt(3/4) 

cosx = sqrt(3)/2 or -sqrt(3)/2 

x = pi/6, 11pi/6 or 5pi/6, 7pi/6 

x = 30, 330 or 150, 210


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