A student Carried out the titluhon. Sodium hydroscide against sulphuric acid, He did three
litrations of aroma
Solution to obtain the following readings 22.00
or 0.5m sodium hydroxide
,
Calculate the Concentration
of sulphuric acid in molarity (m)
22.10 and 22.20 cms​

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

answer by yourhope:

how do models compare to real-world objects?

d. most models represent a real-world object in a simpler way.

: )

it is the most commonly accepted one

може ли да зареждате повече информация, моля