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5. What type of reaction would the heat calculation in previous question be classified as?

A) Natural

B) Chemical

C) Endothermic

D) Exothermic

7. What causes the volume to change in gases? (Choose all that apply)

A) Density

B) Temperature

C) Shape of container

D) Pressure

for the first one we need the previous question to be able to answer it. for the second one density and temperature

Explanation:

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :