If 1.3 moles of silicon dioxide react with 2.5 moles of carbon, how many grams of carbon monoxide form?

46.76 g

Explanation:

The reaction that takes place is:

First we determine the limiting reactant:

1.3 moles of SiO₂ would react completely with (3 * 1.3) 3.9 moles of C. There are not as many C moles, meaning that C is the limiting reactant.

Now we convert C moles (the limiting reactant) into CO moles, using the stoichiometric coefficients:

Finally we convert 1.67 moles of CO to grams, using its molar mass:

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