How many moles are present when there are 1.00 * 10 to the 26 power

166.11 mol

Explanation:

I hope you mean molecules

1 mol of anything is 6.02 * 10^23

x mol of anything is 1 * 10^26

1/x = 6.02 * 10^23/1 * 10^26              Cross multiply

1 * 1*10^26 = 6.02*10^23 * x              Divide by 6.02*10^23

1*10^26/6.02 * 10^23 = x

x = 166.11 mol

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation:

answer is a

explanation: