I’d appreciate any help

27 g

Explanation:

From the question,

n = Mv Equation 1

Where n = number of mole of Al₂SO₄,  M = Molarity of Al₂SO₄, v = Volume of the solution.

Given: M = 0.12 mol/L, v = 1.5 L.

Substitute these values into equation 1

n = 0.12×1.5

n = 0.18 mol

Also,

n = Mass(m)/Molar mass (m')

n = m/m'.

m = n×m' Equation 2

Given: The molar mass of Al₂SO₄ = (27×2)+32+(16×4) = 150 g/mol

Substitute into equation 2

m = 0.18×150

m = 27 g

the answer to your question is c