13. A 90 ml solution of 12 m base needs how many moles of acid to neutralize the base? a.10.8 moles
b. 1080 moles
C. 7.5 moles
d. 1.08 moles

d is right

Explanation: amount of instance of the base is n= cV = 12mol/l · 0.09 l.

Also same amount. Of acid is needed

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