When the volume and concentration of a base that completely neutralizes an acid is known, you can determine the concentration of the acid due to at the point of neutralization, the number of moles of acid equals the number of moles of base. why does this happen? (btw this is describing titration) the criteria for the answer is
"Try to answer why the results occurred. If you are in chemistry, what is happening at the molecular level with bonding, electrons, etc. " WILL MARK BRAINLIEST

Titration of a strong acid with a strong base is the simplest of the four types of titrations as it involves a strong acid and strong base that completely dissociate in water, thereby resulting in a strong acid-strong base neutralization reaction. This titration requires the use of a buret to dispense a strong base into a container of strong acid, or vice-versa, in order to determine the concentration of the strong acid/base. A strong acid-strong base reaction always results in a net ionic equation of just water. Since neither H+ nor OH- molecules remain in the solution (they form water), we can conclude that at the equivalence point of a strong acid-strong base reaction, the pH is always equal to 7.0.

Further adding acid or base after reaching the equivalence point will lower or raise the pH, respectively.

We can plot this to show the titration curve. Our analyte would be HCl and our titrant would be NaOH (this is arbitrary). Before any NaOH is added, we have an acidic solution (it predominantly contains H₃O⁺ from the dissociation of HCl). Since HCl is a strong acid, the pH is relatively low. As we slowly drop NaOH, the pH slowly rises due to still having more H₃O⁺ than OH⁻ (from dissociation of NaOH). Eventually, the number of moles of NaOH added = moles of HCl initially there. At this point, all of the H₃O⁺ ions created from the dissociation of HCl have been completely neutralized by the OH⁻ ions created from the dissociation of NaOH. The solution now only has NaCl (neutral salt) and water (the Cl and Na ions are spectator ions), and therefore the pH is 7. The equivalence point takes place at the pH of 7. Now, the addition of NaOH molecules makes the solution basic and the pH will exceed 7 as there is now an excess of OH⁻ as opposed to H₃O⁺.

Explanation: hope that helped- i took one of my quizlets so i dont know

58750.08068 is the answer i think