A 1.5 L pocket of air with a temperature of 295 K rises in the atmosphere. What will be the volume of the air pocket of the t temperature decreased to 2 celsius and the pressure is not changed.

1.4 L.

Explanation:

Applying Charles law,

V/T = V'/T' Equation 1

Where V = Initial volume, V' = Final volume, T = Initial Temperature in Kelvin, T' = Final Temperature in Kelvin.

Make V' the subject of the equation

V' = (V/T)T' Euqation 2

Given: V = 1.5 L, T = 295 K, T' = 2 °C = (2+273) K = 275 K

Substitute these values into equation 2

V' = (1.5/295)275

V' = 1.398

V' ≈ 1.4 L

it should have an internal chamber and two thermometers sticking out of the top. the internal chamber will also be closed off from the outside.