Chemistry, 11.04.2021 14:00 Alysssssssssssa
A reaction has activation energy of 85kjper mol. What is the effect on the rate of raising the temperature from 20degree to 30 degree
Answers: 3
![ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]](/tpl/images/1251/2424/c502b.png)
= rate constant at temp 
= rate constant at temp 
= activation energy
![ln \frac{k_{2}}{k_{1}} = \frac{-85\times 1000J/mol}{8.314J/Kmol}[\frac{1}{303} - \frac{1}{293}]](/tpl/images/1251/2424/a6735.png)
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A reaction has activation energy of 85kjper mol. What is the effect on the rate of raising the tempe...
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