1. Suppose you have 1.00 mol of liquid water at 0.0 C and add just enough heat to bring the temperature of the water to 100.0 °C, but no more heat is added. How much heat was added?

Heat Q = m·c·ΔT

Explanation: Mass of 1.00 mol water m= 18.016 g. Heat capacity of water is

c= 4.19 J/( g K) and change of temperature ΔT= 100 K

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

practical process described pest part of scientific investigation.

because practical knowledge is powerful then therotical knowledge.