Car q and z are put though an endurance test to see if they can travel at 120 km/h for 5.0 hours. each car has a 45-l fuel tank. car z must stop to refuel after traveling for 4.2 hours. car q, however, travels for 5.4 hours before running out of gas. for each car, calculate the average kilometers traveled for each liter of gas (km/l)

Explanation:

For car Z, according to the Newton equation,

                       v = u + at

where,    v = final velocity = 0

              u = initial velocity = 120 km/h

              a = acceleration

              t = time = 4.2 hours

Putting the given values into the above formula as follows.

                v = u + at

                0 =

                 a = 28.571

Also, it is known that

                             s =

Putting the values into the above formula calculate for 's' as follows.

                  s =

                     =

                     = 252.0 km

Since, 45 L of fuel is used by the car to travel 252 km. Then calculate car traveled km per liter as follows.

                      = 5.6 km/L

For car Q,        v = u + at

                      0 =

                       a =

                          = 22.22

Now, calculate value of 's' for car Q as follows.

                      s =

                     =

                     = 324.0 km

Hence, average kilometers traveled for liter of gas is as follows.

                        7.2 km/L

Thus, we can conclude that the average kilometers traveled for each liter of gas (km/L) by car Z is 5.6 km/L and for car Q is 7.2 km/L.

yes

explanation:

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