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The molality of solution is 1.2 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

where,

n = moles of solute

= weight of solvent in kg

Given : 10 g of glycerol is present in 100 g of solution

moles of glycerol =

mass of water (solvent )= (100-10) = 90 g = 0.09 kg

Now put all the given values in the formula of molality, we get

Therefore, the molality of solution is 1.2 mole/kg

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

i dont know

explanation: