A 5.0-g sample of Substance X increases in temperature from 20.0°C to 22.0°C when it absorbs 9.6J of heat. What is the specific heat of Substance X in J/g °C)?

0.96 J/g °C

General Formulas and Concepts:

Thermochemistry

Specific Heat Formula: q = mcΔT

Explanation:

Step 1: Define

[Given] m = 5.0 g

[Given] ΔT = 22.0 °C - 20.0 °C = 2.0 °C

[Given] q = 9.6 J

[Solve] c

Step 2: Solve for c

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.