6. Calculate Limiting Reagent in this reaction knowing that you are given 30 grams of Octane and 30 grams of Oxygen gas; which one is the LR when you consider product of Carbon dioxide?
2 C8H18(l)+ 25 O2(g) → 16 CO2(g) + 18 H2O(g)

i think its 5049.

i hope this !

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol