Use the graph to answer these questions. 6CO2(g) + 6H2O(g)
C&H 206(s) + 602(g)
The total energy of the products is
O -3,811.92 kJ.
CH1206(s) + O2(g
с
O
-1,273.02 kJ
-1273.02 kJ
-2,538.90 kJ.
DO NE
Energy
A
B
-3811.92 kJ
6CO2(g) + 6H2O(g)
Reaction Progression

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally