Q1. Consider respiration, one of the most common chemical reactions on earth occur according to the reaction:
C6H1206 +602 = 6CO2 + 6H2O + energy
What mass of CO2 forms in the reaction of 25g of glucose with 40g of oxygen?

  First we need to know how many moles of each reactant there are.

C6H12O6 :         25g/180.06g/mol=0.1388mol

O2:                    40g/32g/mol=1.25mol

The equation tells us we need 6 moles of O2 for every 1 mole of Glucose.

6 x 0.1388 = 0.8328

So, we have more O2 then needed – it is in excess.

Glucose is the limiting reagent – we use this for the calculation.

The equation tells us we make 6 moles of CO2 for every 1 mole of Glucose

So, we make 0,8328 moles of Carbon Dioxide

Explanation:

i had this on my unit activity, i can you if you are a plato student. are you a plato student?

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.