If 26.50 g Na2CO3reacted with an excess amount of CuSO4, how many grams of precipitate would be formed?

Na2CO3 + CuSO4 → CuCO3(s) + Na2SO4(aq)

(26.50 g Na2CO3) / (105.98861 g Na2CO3/mol) x (1 mol CuCO3 / 1 mol Na2CO3) x

(123.5554 g CuCO3/mol) = 30.89 g CuCO3

Explanation:

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a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.

gasoline is a mixture. it contains several different kinds of compounds that can be present in a variety of ratios.