Consider the reaction of aluminum chloride with silver acetate. how ml of 0.250m aluminum chloride are required to react completely with 20ml of 0.500m silver acetate?

Answer : The volume of aluminum chloride required are 13.2 mL.

Explanation :

First we have to calculate the moles of silver acetate.

Now we have to calculate the moles of aluminum chloride.

The balanced chemical reaction will be:

From the balanced reaction we conclude that,

As, 3 moles of react with 1 mole of

So, 0.01 moles of react with mole of

Now we have to calculate the volume of aluminum chloride.

Therefore, the volume of aluminum chloride required are 13.2 mL.

there all right good

explanation:

c is the answer because when something is left after something evaporates that shows the chemical change.