A parachute slows a skydiver from 85 m/s to 45 m/s in 4.5 seconds? What is the
acceleration of the parachute?
A. 8.9 m/s2
B. -8.9 m/s
2
C. 0.1 m/s2
D. -0.1 m/s
2

Explanation:

Acceleration is found by dividing the change in velocity by the change in time.

The parachute slows from 85 m/s to 45 m/s. Therefore, the final velocity is 45 meters per second and the initial velocity is 85 meters per second. The time is 4.5 seconds.

Substitute the values into the formula.

Solve the numerator and subtract.

Divide.

If we round this to the nearest tenth, the 8 in the hundredth place tells us to round the 8 up to a 9.

The acceleration of the parachute is approximately -8.9 meters per square second. The value is negative because the parachute is slowing down.

the dissociation of nickel hydroxide is follows:

the concentration of hydroxide ion is

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

thus, concentration of ni is 0.23 * 10^-^4 mol /l