What is the molarity of .65 L of solution containing 63 grams of NaCl? (dont forget to convert grams to moles)

1.66 M

Explanation:

Molarity = moles/L solution

We have the following data:

mass NaCl = m = 63 g

volume of solution = V = 0.65 L

Thus, we first convert the mass to moles with the molar mass of NaCl (MM):

MM(NaCl) = 23 g/mol Na + 35.4 g/mol Cl = 58.4 g/mol

moles NaCl = m/MM = 63 g/(58.4 g/mol)= 1.08 mol

Finally, we divide the moles into the volume of solution to calculate the molarity:

M = moles NaCl/V = 1.66 mol/L

jjj89t'ji; it hink the answer is your mom is not si

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml