4. What is the volume of 6.5 moles of Helium at STP?
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Volume of 6.5 moles of Helium at STP is 145.6954 L

Explanation:

As we know

At STP, temperature is  273.15 K  and pressure is  1 atm

n is the number of moles which is equal to 6.5

R is the gas constant = 0.08206 L atm/K mol

Substituting the given values in above equation, we get -

Liters

Volume of 6.5 moles of Helium at STP is 145.6954 L

answer: lol

explanation:

lol

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j