What is the enthalpy for 2H2S(g) + 3O2(g) -> 2H2O(I) + 2SO2(g). (∆H)​

2H2S (g) + 3O2 (g) → 2H2O (l) + 2SO2 (g)

Calculate ΔH° from the given data. Is the reaction exothermic or endothermic?

ΔH°f (H2S) = -20.15 kJ/mol; ΔH°f (O2) = 0 kJ/, mol; ΔH°f (H2O) = -285.8 kJ/mol; ΔH°f (SO2) = -296.4 kJ/mol

its going to be mutualism cuz they both benefit from the relationship.

~batmans wife dun dun