According to the vsepr theory, what is the shape of a molecule that has a central atom bound to three other atoms with no lone pairs of electrons?

Explanation:

A molecule which contains three bond pairs but no lone pair of electrons will have a trigonal planar geometry.

Hybridization of such a geometry is .

For example, is a trigonal planar molecule.

As, hybridization of will be calculated as follows.

                Hybridization =

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

              Hybridization =

                                    =

                                    = 3

So, the hybridization of will be . As there are 3 bond pairs and no lone pair of electrons. Hence, the geometry of is trigonal planar.

Thus, we can conclude that according to the VSEPR theory, the shape of a molecule that has a central atom bound to three other atoms with no lone pairs of electrons is trigonal planar.

yes it is balanced

- lead + phosphoric acid = hydrogen + lead(ii) phosphate