Zn(s)+2hcl(aq)= zncl2(aq)+h2(g)
0.306 moles of hcl are required to consume all of the zn in th...
Zn(s)+2hcl(aq)= zncl2(aq)+h2(g)
0.306 moles of hcl are required to consume all of the zn in the reaction mixture..
what is the volume of the solution that will deliver the required amount of the concentration is 2.5 m in hcl? what volume is required to prepare this solution from a concentrated (18m)?
Answers: 1
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