There are 342 g of sucrose in 1.00 mol of sucrose. what is the molar concentration (molarity) of a solution containing 171 g sucrose in 1.25l solution?

Given the values above, in order to know the molar concentration or the molarity of a solution containing 171 g of sucrose in 1.25L solution, here is the solution that you should follow: So,
MM = 342 (g/mol) 
171 (g) / 342(g/mol) = x mol of sucrose 
x moles of sucrose/ 1.25 L =  Molarity of solution
Hope this is the answer that you are looking for.