Calculate how many moles of nh3 form when each quantity of reactant completely reacts according to the equation:
3n2h4(l)→4nh3(g)+n2(g)

a.) 2.0 mol n2h4

1) Use the balanced chemical equation to find the molar ratios (proportions) of each product and reactant.

3N2H4(l)→4NH3(g)+N2(g)

=> molar ratios: 3 mol N2H4 : 4 mol NH3

2) Use the product to reactant molar ratio, and the quantity of reactant to determine the yield:

2.0 mol N2H4 * [4mol NH3] / [3mol N2H4] = 2*4/3 mol NH3 = 2.7 mol NH3

2.7 mol
 

2.00 is the !