Correctly classify each of the following compound as highly soluble or insoluble in water. 1. nacl 2. ch3cl 3. ch3oh 4. koh 5. c6h6 6. c6h14 7. kno3 8. ccl4 9. naso4 10. ch3ch2oh 11. ch2cl2 12. ch3cooh

There are solubility rules for inorganic compounds in water as shown in the picture attached. For organic compounds, we use the concept of polarity.

1. NaCl: Since NaCl is a chloride and Na is not included in the list of insoluble, therefore, NaCl is highly soluble.

2. CH₃Cl: This compound is organic. Since the electonegativity between C and Cl is great, it tends to be polar. Because water is also polar, this is highly soluble.

3. CH₃OH: This is an alcohol. Alcohols with short chains of hydrocarbon are highly soluble in water because of hydrogen bonding (-OH).

4. KOH: From the table, KOH is highly soluble. In fact, this is a strong solid which readily dissociates in water.

5.  C₆H₆ is the benzene ring. This is a nonpolar molecule, so you would expect this to be insoluble with water.

6. C₆H₁₄ is hexane which is a long chain of hydrocarbons. Because there is no point of hydrogen bonding, this is nonpolar, and therefore, insoluble in water.

7. KNO₃ is highly soluble because all nitrates are soluble.

8. CCl₄ is an organic compound. Individually, C-Cl bonds are polar. But because there are 4 of them, they cancel out. As a result, there is a balance of partial charges which makes it nonpolar. Thus, this is insoluble in water.

9. NaSO₄: from the table, this is highly soluble.

10. CH₃CH₂OH: Although it is composed of the nonpolar hydrocarbon chain, the OH group is much stronger such that it is highly soluble in water.

11. CH₂Cl₂: This is polar because there is an imbalance due to the C-H and C-Cl bonds. Thus, it is highly soluble in water.

12. CH₃COOH is a carboxylic acid which is even more soluble than alcohols. Thus, this is highly soluble in water.

Ithink 2.2 ibs i think i learned a bit about it

Mass of water is smething that you froma drug test or sum girl ya