A25-ml solution of h2so4 is completely neutralized by 18 ml of 1.0m naoh. what is the concentration of the h2so4?
h2so4(aq) +2naoh(aq) → na2so4(aq) + 2h2o(l)

a.0.72m
b.0.009m
c.0.50m
d.0.36m

We have M1V1=M2V2. Here M1 is to be found, V1=25ml=(25/1000)L & M2=1.0M, V2=18ml=(18/1000)L. Therefore M1=(M2V2)V1
so after putting values we get answer 0.72M.
Hope it helps.

I’d have to say no because without oxygen in the water the fish would all be dead. so if you want to fish for dead fish, pick the ponds with the lowest oxygen concentrations.

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic