An unknown volume of gas has a pressure of 0.50 atm and temperature of 325 k. if the pressure is raised to 1.2 atm and the temperature decreased to 320 k, giving a new volume of 48 l, what was the initial volume?
a. 65 l
b. 87 l
c. 120 l
d. 140 l

You can solve this by using the equation (P1V1/T1) = (P2V2/T2). Plug in 0.50 atm for P1, leave V1 as the unknown, and plug in 325 K as T1. Then substitute 1.2 atm for P2, 48 L for V2, and 320 K for T2. Solve for V1, which is 117L, but since you round using two sig figs, your answer is C, 120 L. Hope this helps!

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