Chemistry, 18.09.2019 06:50 naidaisha18

The densities of crystalline co2 and nh3 at 160 k are 1.56 and 0.84 g/cm3, respectively. calculate their molar volumes.

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Answer from: Svetakotok

The molar volume of carbon dioxide is 28.21cm^3 and that of ammonia is 20.275cm^3

Explanation:

To calculate the molar volume for the given densities, we use the mass to be molar mass.

To calculate volume of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$ ......(1)

For carbon dioxide:

Density of carbon dioxide = 1.56g/cm^3

Molar mass of carbon dioxide = 44.01 g

Putting values in equation 1, we get:

$1.56g/cm^3=\frac{44.01g}{\text{Volume of carbon dioxide}}\\\\\text{Volume of carbon dioxide}=28.21cm^3$

Hence, the molar volume of carbon dioxide is 28.21cm^3

For ammonia:

Density of ammonia = 0.84g/cm^3

Molar mass of ammonia = 17.031 g

Putting values in equation 1, we get:

$0.84g/cm^3=\frac{17.031g}{\text{Volume of ammonia}}\\\\\text{Volume of ammonia}=20.275cm^3$

Hence, the molar volume of ammonia is 20.275cm^3

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

the number of protons in the nucleus of a given element. has slight luster and conducts electricity at high temperatures like metal.but like a nonmetal,boron is brittle and does not conduct electricity well at low temperatures. in graphite, carbon is a soft,brittle solid.it is reflective,ductile,or malleable.

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The densities of crystalline co2 and nh3 at 160 k are 1.56 and 0.84 g/cm3, respectively. calculate t...

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