Calculate the change in energy of an atom that emits a photon of wavelength 2.21 meters. (planck’s constant is 6.626 x 10-34 joule seconds, the speed of light is 2.998 x 108 m/s)
* 8.9886 x10-26 joules
*4.8844 x 10-42 joules second
* 1.9864 x 10-25 joules
* 1.4643 x 10-33 joules /second

Answer : The correct option is,

Solution :

Formula used :

where,

E = change in energy

h = Planck’s constant =

c = speed of light =

= wavelength = 2.21 m

Now put all the given values in the above formula, we get the energy of an atom.

Therefore, the energy of an atom is,

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