Suppose a certain species of insect lives in the lush green canopy of the rain forest. some of the insects are bright green in color, and some are bright yellow. assume there is a natural predator of the insect in the area. what do you expect to happen to the populations of the green and the yellow insects over time? a. the green insect population will increase and the yellow insect population will decrease. b. the green insect population will decrease and the yellow insect population will increase. c. both insect populations will remain constant over time. d. both insect populations will increase over time.

A. The green insect population will increase and the yellow insect population will decrease.

Explanation:

Natural selection is a phenomena of differential survival and reproduction. In this the individuals in the population of the species having beneficial phenotypic traits will survive and reproduce in adverse environmental conditions.

According to the given situation, the green insect population will increase due to the fact that they have green color which mimics the lush green canopy of rainforest. Thus will remain undetected by the predators. But yellow insects can be detected and will be consumed by the predators. Hence, the population of yellow insect will decrease.

This can be concluded that Green color is a better phenotypic trait over yellow among insects of rainforest living in lush green canopy.

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.