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Chemistry, 04.02.2020 20:50 mmaglaya1

The ionic product of water, kw at 298k = 1 x 10^-14.
given that the kw of water at 50 degrees c is 5.47 x 10^-14, calculate the ph of water at this temperature.

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The ionic product of water, kw at 298k = 1 x 10^-14.
given that the kw of water at 50 degrees...
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