Boron has an atomic mass of 10.8 amu. it is known that naturally occurring boron is composed of two isotopes, boron-10 and boron-11. determine the percent of each isotope of boron

Boron -10 : 20%

Boron -11 : 80%

Explanation:

Mass of isotope  boron -10= 10

% abundance of isotope 1 = x% =

Mass of isotope boron-11 = 11

% abundance of isotope 2 = (100-x)% =

Formula used for average atomic mass of an element :

Therefore, percent of boron -10 is 20% and isotope boron-11 is (100-20)= 80%.

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