What is the temperature of a 100 liter container having 1 mole of an ideal gas at a pressure of 20 kilopascals? (given: r = 8.314 l · kpa/k · mol)

For this case, we use the equation for an ideal gas which is expressed as PV=nRT where P is the pressure, V is the volume, n is the number of moles and T is the temperature. We calculate as follows:

PV = nRT
T = PV / nR
T = 20 kPa (100 L) / 1 mol (8.314) 
T = 240.56 K

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