The volume of a sample of gas at 273 k is 100.0 l. if the volume is decreased to 50.0 l at constant pressure, what will be the new temperature of the gas?

Ideal gas equation is PV = nRT.

V/T = nR/P = constant.

Therefore, (V/T)initial = (V/T)final.

100/273 = 50/T

T = 50 x 273/100=136.5 K.

Hope this helps!

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