What is the smallest possible value of the principal quantum number n for an f electron?

For the f electron, the smallest possible principal quantum number is 4.

The principal quantum number is the shell of the atom for the electrons spinning. The electrons are to be distributed on the quantum numbers. The n is the principal quantum number and is the shell.

n can be 1, 2,3,4,5,6, or 7.

The shells are further divided into orbitals.

n = 1 = s

n =2 = s, p

n = 3 = s, p, d

n = 4, 5, 6, 7 = s, p, d, and f.

Thus for the f electron, the smallest possible principal quantum number is 4.

For more information about the principal quantum numbers, refer to the link:

link

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%