In the following reaction, how many grams of ammonia (nh3) will produce 300 grams of n2? 4nh3 + 6no → 5n2 + 6h2o the molar mass of ammonia is 17.0337 grams and that of nitrogen is 28.02 grams.

145.87 grams of ammonia will produce the given amount of nitrogen.

Explanation:

To calculate the moles of nitrogen, we use the formula:

  ....(1)

Given mass of nitrogen = 300 g

Molar mass of nitrogen = 28.02 g/mol

Putting values in above equation, we get:

For the given reaction:

By Stoichiometry of the reaction:

5 moles of nitrogen is produced from 4 moles of ammonia.

So, 10.706 moles of nitrogen will be produced from =

Now, calculating the mass of ammonia, we use equation 1:

Molar mass of ammonia = 17.0337 g/mol

Moles of ammonia = 8.564 mol

Putting values in equation 1, we get:

Hence, 145.87 grams of ammonia will produce the given amount of nitrogen

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2